Deceleration is opposite action of the acceleration. Acceleration is defined as change in velocity by time (increasing the speed), so that deceleration is defined as the rate of decrease of speed of a motion (decrease speed or velocity). The act or process of decelerating is known as deceleration. Otherwise decrease in speed is called **deceleration**

**Example:**

** The rocket is good example for deceleration***.*

## What is Deceleration?:

Deceleration is defined as three ways, there are

- A decrease in rate of change, and
- A rate of decrease in velocity, and
- The act of the decelerating is low (decreasing the speed).

The amount by which a speed or velocity decreases.

Deceleration is reduction in speed, It is a most restricted term. We know that speed of one particle in motion decreases means that when the component of acceleration is opposite side of velocity (opposite direction). In this case, we can say that the particle is may decelerated.

A positive acceleration and negative velocity mean deceleration, so that deceleration is fully indeed opposite to acceleration.

## Important formula for deceleration:

** S = at^2 / 2 = vt / 2 = v^2 / (2a) and **

And deceleration formula is opposite of the acceleration,

Acceleration formula is = (last velocity – first velocity) / total time, so that here for deceleration is just opposite formula (positive is changed into negative).

** Deceleration in Motion is:**

** Deceleration is = initial velocity (speed) – final velocity (speed) / total time.**

** Equation for deceleration:**

** Deceleration = (vi – vf)/t**

So that** Deceleration = – Acceleration**

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## Types of deceleration and Example problem for deceleration:

** Types of deceleration:**

- Uniform deceleration
- Early deceleration
- Variable decelerations
- Late deceleration

Those all are important types in deceleration motion.

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** Example problem for deceleration:**

** Problem:**

** ** A bus is traveling at 100km/hr, when the bus driver sees a car 50m ahead on road, and put breaks. What is the constant deceleration is required to stop the bus in time to avoid hitting?

** Solution:**

Here given, Vi = 100 km/hr,

And d = 50 m, we know Vf =0

So here we have to use the formula for Vf^2 = Vi^2 + 2ad,

So, we have changed some units from given information,

** Vi = 100 km/hr => (100km/hr) * (1000 m/km)*(1/3600hr/sec) = 250 / 9 m/s**

** So, now find **

A = – (250/9) ^2 / (2*50)

= -771.72 / 100

= -7.7172

** So, Answer is a= -7.7172 m/ s^2**