Introduction to slope parameter:
In the introduction part discuss about slope parameter is nothing but we are going to study all the concepts about the slope. In this article going to study about slope parameter and slope fields to learn and how to find the slope parameter of the line if the points are given. Then Slope from the standard form of the line, slope parameter value of the parallel line and perpendicular lines. For the solving slope parameter practice problem are solved.
Details in Slope Parameter:
In the process make of are giving the keywords and we will get all the details about in the slope parameter. If normally slope is nothing but the ratio between the rates of change in the y axis to the rate of change in x axis. The solving slope parameter of the line is indicated by the letter m. We can calculate the slope of the line using the following formula
Slope [m] = `((y_2-y_1)/(x_2-x_1))`
If any two line is parallel then these both lines slope will be equal. Slope of the first line = slope of the second line.
If any two line is perpendicular the second lines slope is negative and reciprocal of the first line. We will see some example problems for finding the slope of the line from the points.
Problem for Solving Slope Parameter:
Problem 1 find slope parameter:
Find the slope of the line where it is passing through the following points (6, 12) and (5, 8).
Given points are (6, 12) and (5,8).
Slope of the line (m) = `(y_2-y_1)/(x_2-x_1)`
Here (x1, y1) = (6, 12) and (x2, y2) = (5, 8).
Slope m = `(8-12)/(5-6)`
= ((-4)/ (-1))= 4
Example 2 find the slope parameter:
Find the slope parameter where it is passing through the following points (12,18) and (19, 22).
Given points are (12,18) and (19, 22).
Slope of the line m =`(y_2-y_1)/(x_2-x_1) `
Here (x1, y1) = (12,18) and (x2, y2) = (19, 22).
Slope m =`(19-12)/(22-18)`